(x^2-4)(x^2+2x-8)=

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Solution for (x^2-4)(x^2+2x-8)= equation: 


Simplifying
(x2 + -4)(x2 + 2x + -8) = 0

Reorder the terms:
(-4 + x2)(x2 + 2x + -8) = 0

Reorder the terms:
(-4 + x2)(-8 + 2x + x2) = 0

Multiply (-4 + x2) * (-8 + 2x + x2)
(-4(-8 + 2x + x2) + x2(-8 + 2x + x2)) = 0
((-8 * -4 + 2x * -4 + x2 * -4) + x2(-8 + 2x + x2)) = 0
((32 + -8x + -4x2) + x2(-8 + 2x + x2)) = 0
(32 + -8x + -4x2 + (-8 * x2 + 2x * x2 + x2 * x2)) = 0
(32 + -8x + -4x2 + (-8x2 + 2x3 + x4)) = 0

Combine like terms: -4x2 + -8x2 = -12x2
(32 + -8x + -12x2 + 2x3 + x4) = 0

Solving
32 + -8x + -12x2 + 2x3 + x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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